I believe V6 is a reordering of V1, not V4. V4 is random aside from the bits spe... | Hacker News

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dwattttt 3 months ago | parent | context | favorite | on: A few secure, random bytes without `pgcrypto`

I believe V6 is a reordering of V1, not V4. V4 is random aside from the bits specifying version & variant, ~6/7 bits.

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