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bonzini
on March 1, 2023
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Bitwise Division
Absolutely not, he needs to compute (63 - x) / 7, where x is computed from a 64-bit integers. There are no bigints involved.
vintermann
on March 1, 2023
[–]
Well, there are variable length integers
involved
, since it's as part of a way of representing variable length integers. But it seems you're right that x is just a regular machine int in this context, as an implementation detail. I misunderstood.
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