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I wonder how effective it would be simply to count vowels mod 2. Much faster to calculate, at least for me.



I suspect there's a strong bias in vowelCount % 2. A quick look at English 100 most common [1] has 1's at 73% and 0's at 27%. That would even out with longer words but I wonder how much. Maybe there's something else that's just as easy with less bias?

[1]https://www.englishclub.com/vocabulary/common-words-100.htm


Hm. That makes this puzzle all the more interesting. Maybe it's because I made a Wordle solver app recently, but word statistics are on my mind.




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