I don't see how that can be, given that the character that's chopped off can tak... | Hacker News

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stavros on June 14, 2011 | parent | context | favorite | on: A possible flaw in open-source bcrypt implementati...

I don't see how that can be, given that the character that's chopped off can take one of 40 values... Or is it case sensitive? Still, nowhere near 256.

daeken on June 14, 2011 [–]

It's not b64 encoding the final byte of the hash, not dropping a b64 character.

stavros on June 14, 2011 | [–]

Ah, I see. You are correct, then. Also, that would make it 64 times, if I were right, it seems.

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