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no, check your math.

number of characters required for 128 bit entropy password using alphanumerics: 21.49[1]. round off to 22

number of characters required for 128 bit entropy password using all printable characters: 19.5[2]. round off to 20.

22/20 = 110%

[1] https://www.wolframalpha.com/input/?i=solve+log_2(62%5Ex)%3D... (under "real solution", click on "approximate form")

[2] https://www.wolframalpha.com/input/?i=solve+log_2(94%5Ex)%3D...




There are about 138k printable characters, not 62.




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